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eccentricity \(e\). Thus \[e=152,100\cdot10^6\,\text{km} - 149,603\cdot10^6\,\text{km} =2,497\cdot10^6\,\text{km}.\] Since for an ellipse the relation \(a^2 = b^2
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Sun to Earth at aphelion and the length of the semi-major axis a gives the eccentricity e. Thus e = 152, 100 · 106 km − 149, 603 · 106 km = 2, 497 · 106 km. Since for
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Sun to Earth at aphelion and the length of the semi-major axis a gives the eccentricity e. Thus e = 152, 100 · 106 km − 149, 603 · 106 km = 2, 497 · 106 km. Since for
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